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If the system of linear equations x – 2y + kz = 1 2x + y + z = 2 3x – y – kz = 3 has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose equation is -
- 4x – 3y – 4 = 0
- 3x – 4y – 4 = 0
- 3x – 4y – 1 = 0
- 4x – 3y – 1 = 0
Correct answer: 4x – 3y – 4 = 0
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