Exams › JEE Main › General
Let f(x) = a x (a > 0) be written as f(x) = f 1 (x) + f 2 (x), where f 1 (x) is an even function and f 2 (x) is an odd function. Then f 1 (x + y) + f 1 (x – y) equals
- 2f 1 (x + y) f 2 (x– y)
- 2f 1 (x + y) f 1 (x – y)
- 2f 1 (x) f 2 (y)
- 2f 1 (x) f 1 (y)
Correct answer: 2f 1 (x) f 1 (y)
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