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Let k ˆ x j ˆ ˆ 2 i ˆ 3 a + + = → and k ˆ j ˆ ˆ i ˆ b + − = → , for some real x. Then r | b a | = × → → is possible if -

1. 2 3 3 r 2 3 ≤ <
2. 2 3 5 r ≥
3. 2 3 5 r 2 3 3 < <
4. 2 3 r 0 ≤ <

Correct answer: 2 3 5 r ≥

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