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Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is 2 x y 2 . If the curve passes through the centre of the circle x 2 + y 2 – 2x – 2y = 0, then its equation is -

1. x log e | y | = 2(x – 1)
2. x log e | y | = 2(x – 1)
3. x 2 log e | y | = –2(x – 1)
4. x log e | y | = x – 1

Correct answer: x log e | y | = 2(x – 1)

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