Exams › JEE Main › General
5 moles of and ideal gas at 100 K are allowed to undergo reversible compresion till its temperature becomes 200 K. If C V = 28J K –1 mol –1 , calculate Δ U and Δ pV
- Δ U = 14J; Δ (pV) = 0.8J
- Δ U = 14kJ; Δ (pV) = 4kJ
- Δ U = 14kJ; Δ (pV) = 18J
- Δ U = 2.8 kJ; Δ (pV) = 0.8kJ
Correct answer: Δ U = 14kJ; Δ (pV) = 4kJ
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →