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Two point charges q 1 ( 10 μ C) and q 2 (–25 μ C) are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is, [take 0 1 4 π ∈ = 9 × 10 9 Nm 2 C –2 ]
- (–81 ˆ i + 81 ˆ j ) × 10 2
- (81 ˆ i – 81 ˆ j ) × 10 2
- (63 ˆ i – 27 ˆ j ) × 10 2
- (–63 ˆ i + 27 ˆ j ) × 10 2
Correct answer: (63 ˆ i – 27 ˆ j ) × 10 2
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