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The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth = 6.4 × 10 3 km) is E 1 and kinetic energy required for the satellite to be in a circular orbit at this height is E 2 . The value of h for which E 1 and E 2 are equal, is :
- 3.2 × 10 3 km
- 1.6 × 10 3 km
- 1.28 × 10 4 km
- 6.4 × 10 3 km
Correct answer: 3.2 × 10 3 km
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