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ExamsJEE MainGeneral

A force acts on a 2 kg object so that its position is given as a function of time as x = 3t 2 + 5. What is the work done by this force in first 5 seconds?

  1. 950 J
  2. 900 J
  3. 875 J
  4. 850 J

Correct answer: 900 J

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