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In a communication system operating at wavelength 800 nm, only one percent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting TV signals of band width 6 MHz are (Take velocity of light c = 3 × 10 8 m/s, h = 6.6 × 10 –34 J-s)
- 3.75 × 10 6
- 4.87 × 10 5
- 6.25 × 10 5
- 3.86 × 10 6
Correct answer: 6.25 × 10 5
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