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Let 2 n ≥ be a natural number and 0 < θ < 2 π . Then ∫ θ θ θ θ − θ + d sin cos ) sin (sin 1 n n / 1 n is equal to - (where C is a constant of integration)

1. C sin 1 1 1 n n n 1 n 1 n 2 + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ θ + − + −
2. C sin 1 1 1 n n n 1 n 1 n 2 + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ θ − − + +
3. C sin 1 1 1 n n n 1 n 1 n 2 + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ θ − − + −
4. C sin 1 1 1 n n n 1 n 1 n 2 + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ θ − + + −

Correct answer: C sin 1 1 1 n n n 1 n 1 n 2 + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ θ − − + −

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