Exams › JEE Main › General
A heat source at T = 10 3 K is connected to another heat reservoir at T = 10 2 K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 WK –1 m –1 , the energy flux through it in the steady state is -
- 200 Wm –2
- 65 Wm –2
- 120 Wm –2
- 90 Wm –2
Correct answer: 90 Wm –2
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →