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The equation of the line passing through (–4, 3, 1), parallel to the plane x + 2y – z – 5 = 0 and intersecting the line 3 – 1 x + = 2 3 – y = 1 – 2 – z is :

1. 3 4 x + = 1 – 3 – y = 1 1 – z
2. 1 4 x + = 1 3 – y = 3 1 – z
3. 1 – 4 x + = 1 3 – y = 1 1 – z
4. 2 4 – x = 1 3 y + = 4 1 z +

Correct answer: 3 4 x + = 1 – 3 – y = 1 1 – z

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