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ExamsJEE MainGeneral

For any θ ∈ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π π 2 , 4 , the expression 3(sin θ – cos θ ) 4 + 6(sin θ + cos θ ) 2 + 4sin 6 θ equals :

  1. 13 – 4 cos 4 θ + 2sin 2 θ cos 2 θ
  2. 13 – 4 cos 2 θ + 6sin 2 θ cos 2 θ
  3. 13 – 4 cos 2 θ + 6 cos 4 θ
  4. 13 – 4 cos 6 θ

Correct answer: 13 – 4 cos 6 θ

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