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A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is :
- 508 pJ
- 692 pJ
- 560 pJ
- 600 pJ
Correct answer: 508 pJ
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