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ExamsJEE MainGeneral

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is -

  1. 11 × 10 –5 W
  2. 11 × 10 –3 W
  3. 11 × 10 5 W
  4. 11 × 10 –4 W

Correct answer: 11 × 10 –5 W

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