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If the area of the triangle whose one vertex is at the vertex of the parabola, y 2 + 4(x – a 2 ) = 0 and the other two vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is
- 5 5
- (10) 2/3
- 5(2 1/3 )
- 5
Correct answer: 5
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