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The solution of the differential equation, dx dy = (x – y) 2 , when y

1. = 1, is :
2. –log e y x 1 y x 1 + − − + = x + y – 2
3. log e y 2 x 2 − − = x – y
4. log e x 2 y 2 − − = 2(y – 1) (4) –log e y x 1 y x 1 − + + − = 2(x – 1)

Correct answer: log e x 2 y 2 − − = 2(y – 1) (4) –log e y x 1 y x 1 − + + − = 2(x – 1)

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