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The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians) :
- 8 π
- 6 π
- 4 π
- 3 π
Correct answer: 6 π
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