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A pendulum is executing simple harmonic motion and its maximum kinetic energy is K 1 . If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K 2 . Then :
- 2 K K 1 2 =
- K 2 = 2K 1
- K 2 = K 1
- 4 K K 1 2 =
Correct answer: K 2 = 2K 1
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