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The circuit shown below contains two ideal diodes, each with a forward resistance of 50 Ω . If the battery voltage is 6 V, the current through the 100 Ω resistance (in Amperes) is : 150 Ω 75 Ω 100 Ω 6 V D 1 D 2
- 0.027
- 0.030
- 0.036
- 0.020
Correct answer: 0.020
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