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The ratio of mass percent of C and H of an organic compound (C x H y O z ) is 6 : 1. If one molecule of the above compound (C x H y O z ) contains half as much oxygen as required to burn one molecule of compound C x H y completely to CO 2 and H 2 O. The empirical formula of compound C x H y O z is -

1. C 3 H 6 O 3
2. C 2 H 4 O
3. C 3 H 4 O 2
4. C 2 H 4 O 3 Students may find similar question in CP exercise sheet : [ JEE Main, Chapter : Mole Concept, Ex. # 4, Page 24, Q. No. 19 ]

Correct answer: C 2 H 4 O 3 Students may find similar question in CP exercise sheet : [ JEE Main, Chapter : Mole Concept, Ex. # 4, Page 24, Q. No. 19 ]

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