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Two masses m 1 = 5 kg and m 2 = 10 kg, connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0.15. The minimum weight m that should be put on top of m 2 to stop the motion is - m 1 T T m m 2 m 1 g

1. 18.3 kg
2. 27.3 kg
3. 43.3 kg
4. 10.3 kg Students may find similar question in CP exercise sheet : [ JEE Advance, Chapter : Newtons laws of motion, Level # 1, Q. No. 57 ]

Correct answer: 27.3 kg

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