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The distance of the point (1, 3, –7) from the plane passing through the point (1, –1, –1), having normal perpendicular to both the lines 1 1 – x = 2 – 2 y + = 3 4 – z and 2 2 – x = 1 – 1 y + = 1 – 7 z + , is :

1. 83 10
2. 83 5
3. 74 10
4. 74 20 Students may find similar question in CP exercise sheet : [ JEE Advance, Chapter : 3D, Page 110, Ex. 2, Q. No. 17 ]

Correct answer: 83 10

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