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For any three positive real numbers a, b and c, 9(25a 2 + b 2 ) + 25(c 2 – 3ac) = 15b(3a + c). Then
- b, c and a are in A.P.
- a, b and c are in A.P.
- a, b and c are in G.P.
- b, c and a are in G.P. Students may find similar question in CP exercise sheet : [ JEE Main, Chapter : Progression, Page 27, Ex. 4, Q. No. 19 ] [ JEE Advance, Chapter : Progression, Page 20, Ex. 2, Q. No. 26 ]
Correct answer: b, c and a are in A.P.
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