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Let P be the point on the parabola, y 2 = 8x which is at a minimum distance from the centre C of the circle, x 2 + (y + 6) 2 = 1. Then the equation of the circle, passing through C and having its centre at P is -

1. x 2 + y 2 – 4x + 8y + 12 = 0
2. x 2 + y 2 – x + 4y – 12 = 0
3. x 2 + y 2 – 4 x + 2y – 24 = 0
4. x 2 + y 2 – 4x + 9y + 18 = 0

Correct answer: x 2 + y 2 – 4x + 8y + 12 = 0

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