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An inductor (L = 0.03 H) and a resistor (R = 0.15 k Ω ) are connected in series to a battery of 15V EMF in a circuit shown below. The key K 1 has been kept closed for a long time. Then at t = 0, K 1 is opened and key K 2 is closed simultaneously. At t = 1 ms, the current in the circuit will be : (e 5 ≅ 150) 15 V K 1 K 2 0.15 k Ω 0.03 H
- 100 mA
- 67 mA
- 6.7 mA
- 0.67 mA
Correct answer: 0.67 mA
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