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If f and g are differentiable functions in [0, 1] satisfying f(0) = 2 = g

1. , g(0) = 0 and f
2. = 6, then for some c ∈ ]0, 1[ :
3. f ′ (c) = 2g ′ (c)
4. 2f ′ (c) = g ′ (c) (3) 2f ′ (c) = 3g ′ (c) (4) f ′ (c) = g ′ (c)

Correct answer: , g(0) = 0 and f

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