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The locus of the foot of perpendicular drawn from the centre of the ellipse x 2 + 3y 2 = 6 on any tangent to it is :

1. (x 2 + y 2 ) 2 = 6x 2 – 2y 2
2. (x 2 – y 2 ) 2 = 6x 2 + 2y 2
3. (x 2 – y 2 ) 2 = 6x 2 – 2y 2
4. (x 2 + y 2 ) 2 = 6x 2 + 2y 2

Correct answer: (x 2 + y 2 ) 2 = 6x 2 + 2y 2

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