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The integral dx e x 1 x 1 x 1 x ∫ +       − + is equal to

1. –x x 1 x e + + c
2. (x – 1) x 1 x e + + c
3. x x 1 x e + + c
4. (x + 1) x 1 x e + + c

Correct answer: x x 1 x e + + c

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