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Given 0 Cr / Cr 3 E + = – 0.74 V; 0 Mn / MnO 2 4 E + − = 1.51 V 0 Cr / O Cr 3 2 7 2 E + − = 1.33 V; 0 Cl / Cl E − = 1.36 V Based on the data given above, strongest oxidizing agent will be -

1. Mn 2+
2. − 4 MnO
3. Cl –
4. Cr 3+

Correct answer: − 4 MnO

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