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The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be : (R = 8.314 JK –1 mol –1 and log 2 = 0.301)
- 58.5 kJ mol –1
- 60.5 kJ mol –1
- 53.6 kJ mol –1
- 48.5 kJ mol –1
Correct answer: 53.6 kJ mol –1
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