Exams › JEE Main › Chemistry › Stereochemistry / Isomerism
2 questions with worked solutions.
Answer: 4
(i) C(CH3)(OH)=CH-: left C bears OH and CH3 (different); right C bears H and C(F)(CH3)2 (different) -> YES. (ii) C(CH3)(CH3)=: two identical CH3 on left C -> NO. (iii) CH3-N(=O)-OH: N=O with N carrying CH3 and OH (different) -> shows syn/anti isomerism -> YES. (iv) C(CH3)=CH-: left C bears CH3 and N-group (different); right C bears H and CH(CH3)2 (different) -> YES. (v) C=O: one side is only O -> NO. (vi) C(CH3)2=: two CH3 on one carbon -> NO. (vii) Two different substituents on each double-bond carbon in the ring -> YES. (viii) C=C(CH2CH3)2: right C has two identical ethyl groups -> NO. (ix) C=C(CH3)2: right C has two CH3 -> NO. Count: (i), (iii), (iv), (vii) = 4.
Q2. Which of the following compounds will show geometrical (cis-trans) isomerism?
Answer: (B) A cyclohexene ring with identical D substituents on the two carbon atoms adjacent to and on the same side as the double bond.
In cyclohexene (option B), the two sp3 carbons each carry one D and one H substituent; since neither carbon has two identical groups, restricted rotation in the ring fixes their relative orientation, giving rise to cis and trans isomers. The geminal dichloro group in option A prevents G.I. at that center; the spiro polycyclopropane in option C has no appropriate stereocenters; the diene in option D places the D-substituted carbons on sp2 centers that cannot show classical cis-trans ring isomerism.