Exams › JEE Main › Chemistry › Qualitative Inorganic Analysis
1 questions with worked solutions.
Answer: (NH4)3PO4 * 12MoO3
When a phosphate solution is treated with ammonium molybdate in excess nitric acid and warmed, a characteristic canary yellow precipitate of ammonium phosphomolybdate, (NH4)3PO4 * 12MoO3, is formed, confirming the presence of phosphate ions.