Exams › JEE Main › Chemistry
Among the following carbocations, which one would you expect to undergo a rearrangement (hydride or alkyl shift) to form a more stable cation? (Cations: a secondary carbocation that can shift to become tertiary, versus already-tertiary or already-most-stable cations.)
- A secondary carbocation adjacent to a carbon bearing a methyl group, which can rearrange to a more stable tertiary cation
- A tertiary carbocation that is already maximally stabilized
- A symmetric cation where any shift gives an equally stable cation
- A resonance-stabilized allylic/benzylic cation
Correct answer: A secondary carbocation adjacent to a carbon bearing a methyl group, which can rearrange to a more stable tertiary cation
Solution
Carbocation rearrangements (1,2-hydride or 1,2-alkyl shifts) occur when they convert a less stable cation into a more stable one. A secondary carbocation positioned next to a carbon bearing additional alkyl substitution (e.g. a methyl-substituted ring carbon) will undergo a 1,2-shift to generate a tertiary carbocation, which is more stable. An already-tertiary, symmetric, or resonance-stabilized cation has no driving force to rearrange. Hence the secondary-to-tertiary case is the one expected to rearrange.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →