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ExamsJEE MainChemistry

Given the standard reduction potentials: Fe2+ + 2e- -> Fe; E° = -0.41 V Ag+ + e- -> Ag; E° = +0.80 V O2 + 2H2O + 4e- -> 4OH-; E° = +0.40 V A bar of silver is joined by a wire to an iron pipe buried underground. What is the expected outcome?

  1. The silver would corrode, a current would flow in the wire, and O2 would be reduced at the iron pipe surface.
  2. The silver would corrode, a current would flow in the wire, and Fe2+ would be reduced at the iron pipe surface.
  3. The iron pipe would corrode, a current would flow in the wire, and Ag+ would be reduced at the silver surface.
  4. The iron pipe would corrode, no current would flow in the wire, and O2 would be reduced at the iron pipe surface.

Correct answer: The iron pipe would corrode, a current would flow in the wire, and Ag+ would be reduced at the silver surface.

Solution

Iron (E° = -0.41 V) is much more easily oxidized than silver (E° = +0.80 V). When the two are connected, a galvanic cell forms: iron is the anode and corrodes, while reduction occurs at the silver (cathode). Since the electrodes have different potentials, a net cell emf drives a current through the wire. At the silver cathode, the species with high reduction potential present (Ag+ from any dissolved silver, in the option's framing) is reduced. Note this is harmful — it accelerates iron corrosion, unlike a sacrificial anode (e.g., Mg or Zn) which would protect the iron.

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