Correct answer: five-membered ring with N+H2 and two double bonds
For aromaticity every ring atom must contribute a p-orbital to a continuous conjugated loop. In the five-membered ring drawn with N+H2 and two double bonds, the nitrogen is sp3 (it carries two H atoms and no p-orbital available to the ring system in the conjugated sense), so the cyclic conjugation is broken: this species is non-aromatic. Furan (five-membered O ring with two double bonds) is aromatic (O donates a lone pair, 6 pi electrons). The fused bicyclic diaza system is stated to be aromatic, and borazine (B3N3H6, 'inorganic benzene') is aromatic. Hence only the N+H2 ring is non-aromatic.