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A galvanic cell is set up using a copper rod immersed in 1 M CuSO4 and a nickel rod immersed in 1 M NiSO4. Given the standard reduction potentials E(Cu2+/Cu) = +0.34 V and E(Ni2+/Ni) = -0.25 V, what is the standard EMF of the cell?
- 0.59 V
- 0.09 V
- 0.85 V
- 0.34 V
Correct answer: 0.59 V
Solution
Copper has the higher reduction potential (+0.34 V), so Cu is reduced (cathode) and Ni is oxidized (anode). The cell is Ni | Ni2+ (1M) || Cu2+ (1M) | Cu, and the standard EMF is the difference of the reduction potentials.
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