Exams › JEE Main › Chemistry

For the redox reaction A(s) + 2B+(aq) -> A2+(aq) + 2B(s), the equilibrium constant Kc is found to be 10¹² at 298 K. Determine the standard cell potential E°cell.

1. 0.354 V
2. 0.708 V
3. 0.0098 V
4. 1.36 V

Correct answer: 0.354 V

Solution

At equilibrium the standard cell potential is linked to the equilibrium constant by E°cell = (0.059/n) log Kc. With n = 2 and log(10¹²) = 12, E°cell = (0.059/2) * 12 = 0.0295 * 12 = 0.354 V.

Related JEE Main Chemistry questions

• During electrolysis of an aqueous solution of dipotassium succinate, which gas is evolved at the electrodes?
• Which expression gives the equivalent conductance at infinite dilution of Al2(SO4)3, if Λ°Al3+ and Λ°SO4²− denote the equivalent conductances at infinite dilution of the corresponding ions?
• The standard emf of a Daniell cell is 1.10 V. What is the greatest amount of electrical work that can be extracted from this cell?
• During the recharging of a lead storage battery, which reaction takes place at the cathode?
• The limiting molar ionic conductivities of the ions X2+ and Y2− are 57 and 73, respectively. What will be the molar conductivity of the electrolyte formed by these ions?
• According to Kohlrausch’s law, at what condition does each ion contribute a fixed amount to the conductance of an electrolyte, irrespective of the other ion present?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →