Exams › JEE Main › Chemistry

For a hydrogen electrode operating at 25 deg C with P(H2) = 1 atm and [H+] = 0.1 M, what is its reduction potential?

1. 0.00 V
2. -0.059 V
3. 0.118 V
4. 0.059 V

Correct answer: -0.059 V

Solution

Because [H+] is less than 1 M, the electrode is a weaker reducer of H+ than the SHE, so the reduction potential becomes negative. At [H+] = 0.1 M the shift is exactly -0.059 V.

Related JEE Main Chemistry questions

• During electrolysis of an aqueous solution of dipotassium succinate, which gas is evolved at the electrodes?
• Which expression gives the equivalent conductance at infinite dilution of Al2(SO4)3, if Λ°Al3+ and Λ°SO4²− denote the equivalent conductances at infinite dilution of the corresponding ions?
• The standard emf of a Daniell cell is 1.10 V. What is the greatest amount of electrical work that can be extracted from this cell?
• During the recharging of a lead storage battery, which reaction takes place at the cathode?
• The limiting molar ionic conductivities of the ions X2+ and Y2− are 57 and 73, respectively. What will be the molar conductivity of the electrolyte formed by these ions?
• According to Kohlrausch’s law, at what condition does each ion contribute a fixed amount to the conductance of an electrolyte, irrespective of the other ion present?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →