Exams › JEE Main › Chemistry
A KOH aqueous solution is 6.50 molal and has density 1.89 g/cm³. Calculate its molarity in mol/dm³ (round to the nearest integer). [Molar masses: K = 39.0, O = 16.0, H = 1.0]
- 9
- 11
- 13
- 7
Correct answer: 9
Solution
Molar mass of KOH = 56 g/mol. For 6.50 mol in 1 kg water, total mass = 1364 g, volume = 1364/1.89 = 721.7 mL, giving molarity = 6.50/0.7217 = 9.0 mol/dm³.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →