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What volume (in mL) of 0.8 M AlCl3 must be combined with 50 mL of 0.2 M CaCl2 so that the resulting solution has a chloride ion concentration of 0.6 M?
- 5.0
- 5.56
- 10.0
- 12.5
Correct answer: 5.56
Solution
Setting up the chloride balance, (2.4 V + 0.02)/(V + 0.05) = 0.6 gives V ~ 0.00556 L = 5.56 mL.
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