What mass of BaCl2 (in grams) is required to prepare 250 mL of a solution whose chloride-ion concentration equals that of a solution containing 1.825 g HCl per 100 mL? (Ba = 137, Cl = 35.5, H = 1)

Question

Accepted Answer

13.0 g. The HCl gives 0.5 mol/L Cl-; in 250 mL that is 0.125 mol Cl-; BaCl2 supplies 2 Cl- each, so 0.0625 mol BaCl2 * 208 g/mol = 13.0 g.

What mass of BaCl2 (in grams) is required to prepare 250 mL of a solution whose chloride-ion concentration equals that of a solution containing 1.825 g HCl per 100 mL? (Ba = 137, Cl = 35.5, H = 1)

Solution

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