Using several experiments at different initial concentrations 'a' for a given reaction, it is observed that t1/2 is directly proportional to 'a'. What is the order of the reaction?

Correct answer: 0

Solution

For an nth order reaction t1/2 is proportional to a^(1-n); since t1/2 is proportional to a (power 1), 1-n = 1 gives n = 0.

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