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At 46 deg C, Kp for the reaction N2O4(g) <-> 2 NO2(g) equals 0.667 atm. Calculate the percent dissociation of N2O4 at 46 deg C when the total pressure is 380 Torr.

1. 50%
2. 25%
3. 67%
4. 33%

Correct answer: 50%

Solution

With P = 0.5 atm, Kp = 4a² P/(1 - a²) gives a = 0.5, so N2O4 is 50% dissociated.

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