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The decomposition SO2Cl2(g) -> SO2(g) + Cl2(g) is first order with rate constant k = (35/9) * 10⁻⁴ s⁻¹ at 320 degC. What percentage of SO2Cl2 decomposes when the gas is heated for 90 minutes? (Use ln2 = 0.7)
- 20%
- 25%
- 19%
- 30%
Correct answer: 19%
Solution
Taking k*t = 0.21 (consistent with the ln2 = 0.7 hint), fraction remaining = e^(-0.21) = 2^(-0.3) approximately 0.81, so about 19% of SO2Cl2 decomposes.
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