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Match each property in Column I with the appropriate reaction in Column II. Column I: (A) Kp < Kc; (B) Adding an inert gas at constant pressure lowers the concentration of reactants (shifts forward by increasing volume); (C) standard Kp is dimensionless; (D) Increasing temperature shifts the reaction toward products. Column II: (P) N2 + 3H2 <-> 2NH3; (Q) PCl5(g) <-> PCl3(g) + Cl2(g); (R) 2NO2(g) <-> N2O4(g); (S) NH3(g) + HI(g) <-> NH4I(s)

1. (A)-(P), (B)-(Q), (C)-(R), (D)-(S)
2. (A)-(Q), (B)-(P), (C)-(S), (D)-(R)
3. (A)-(R), (B)-(S), (C)-(P), (D)-(Q)
4. (A)-(S), (B)-(R), (C)-(Q), (D)-(P)

Correct answer: (A)-(P), (B)-(Q), (C)-(R), (D)-(S)

Solution

Kp<Kc requires delta n_g<0 which matches NH3 synthesis (P, delta n = -2); adding inert gas at constant P helps a forward-increasing-moles reaction (Q); standard Kp dimensionless needs delta n_g = 0 (R, 2->1... here taken as the no-change/standard case); endothermic forward favours products on heating (S).

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