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For the gas-phase equilibrium 2H2O(g) + 2Cl2(g) <-> 4HCl(g) + O2(g), Kp = 12 x 10⁸ atm at temperature T. Cl2, HCl and O2 are mixed so that each has a partial pressure of 2 atm, and the mixture is then placed in contact with excess liquid water (vapour pressure of water at T = 380 mm Hg). What is the approximate equilibrium partial pressure of Cl2 (in units of 10⁻³ atm)?
- 0.16
- 0.33
- 0.65
- 1.30
Correct answer: 0.33
Solution
Setting P(H2O) = 0.5 atm and P(HCl) = P(O2) = 2 atm, P(Cl2) = sqrt[P(HCl)⁴ * P(O2) / (P(H2O)² * Kp)] = 3.3 x 10⁻⁴ atm = 0.33 x 10⁻³ atm.
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