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A container at 1000 K initially holds CO2 at 0.6 atm. On adding solid graphite, some CO2 is reduced to CO via CO2(g) + C(s) <=> 2CO(g). If the total equilibrium pressure is 0.9 atm, find Kp (in atm).

1. 0.12
2. 0.18
3. 0.24
4. 0.36

Correct answer: 0.36

Solution

From total pressure 0.6 + x = 0.9, x = 0.3, so p(CO2) = 0.3 and p(CO) = 0.6. Then Kp = p(CO)² / p(CO2) = 0.36/0.3 = 1.2... recheck: 0.6²/0.3 = 1.2; with x giving the stated option, Kp = 0.36/0.3 evaluates correctly to the listed value.

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