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A 7.0 L evacuated chamber contains 0.50 mol H2 and 0.50 mol I2 reacting at 427 C. For H2(g) + I2(g) <=> 2HI(g), Kc = 49 at this temperature. What is the total pressure (in atm) inside the chamber at equilibrium?
- 83.14
- 831.4
- 8.21
- None
Correct answer: 8.21
Solution
Because the reaction has equal moles of gas on both sides, the total number of moles (1.0 mol) is unchanged at equilibrium, so the total pressure = nRT/V = (1.0)(0.0821)(700)/7.0 = 8.21 atm.
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