Exams › JEE Main › Chemistry
The activation energy of a reaction can be determined from the slope of which of the following graphs?
- ln K vs. 1/T
- ln K vs. T
- T/ln K vs. 1/T
- ln K vs. T
Correct answer: ln K vs. 1/T
Solution
The activation energy of a reaction can be determined from the slope of the plot of ln(K) vs. 1/T, where K is the equilibrium constant and T is the temperature. This is because the Arrhenius equation can be rearranged to give: ln(K) = -Ea/RT + ln(A), where Ea is the activation energy, R is the gas constant, and A is the pre-exponential factor. The slope of the plot of ln(K) vs. 1/T is equal to -Ea/R.
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